જો પ્રદેશમાં V = 4x^2 વોલ્ટ હોય તો (1, 0, 2) | vedclass

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Question

Step $1:$ Electric field at general point $(x, y, z)$

Given, Potential function as $V =4 x ^2$

Therefore, Electric field $E$ is given by:

$\o

Vedclass · Accepted Answer

$(-x)$ અક્ષની દિશામાં $8 \,V/m$,

Vedclass · Answer

Step $1:$ Electric field at general point $(x, y, z)$

Given, Potential function as $V =4 x ^2$

Therefore, Electric field $E$ is given by:

$\overrightarrow{ E }=\frac{-\partial V }{\partial x } \hat{ i }-\frac{\partial V }{\partial y } \hat{ j }-\frac{\partial V }{\partial z } \hat{ k }$

$\overrightarrow{ E }=\frac{-\partial}{\partial x }\left(4 x ^2\right) \hat{1}-\frac{\partial}{\partial y }\left(4 x ^2\right) \hat{ j }-\frac{\partial}{\partial z }\left(4 x ^2\right) \hat{ k }$

$\overrightarrow{ E }=-8 x \hat{1}-0-0$

$\overrightarrow{ E }=-8 x \hat{ i }$

Step $2:$ Electric field at point $(1,0,2)$ by putting value

$\overrightarrow{ E }=-8 x \hat{ i }=-8(1) \hat{1}$

$\vec{E}=-8 \hat{1}$

જો પ્રદેશમાં $V = 4x^2$ વોલ્ટ હોય તો $(1, 0, 2)\ m$.આગળ વિદ્યુતક્ષેત્ર ........ છે.

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