The dimensional formula of potential difference is ........

  • A
    $ML^2 T^{-3} A^{-1}$
  • B
    $ML^2 T^{-2} Q^{-1}$
  • C
    $MLT^{-2} Q^{-1}$
  • D
    $ML^2 T^{-1} Q^{-1}$

Explore More

Similar Questions

$Assertion$ : The dimensional formula for relative velocity is the same as that of the change in velocity.
$Reason$ : Relative velocity of $P$ with respect to $Q$ is the ratio of the velocity of $P$ and that of $Q$.

The wave equation is given by $Y = A \sin \omega \left( \frac{x}{v} - k \right)$,where $\omega$ is the angular velocity and $v$ is the linear velocity. What is the dimension of $k$?

If the dimensions of a physical quantity are given by $M^aL^bT^c$,then the physical quantity will be:

The velocity of a particle depends upon time as $v = a + bt + ct^2$. If the velocity is in $m/s$,the unit of $a$ will be:

The dimensional formula for angular momentum is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo