If the binding energy per nucleon for $_3{Li}^7$ and $_2{He}^4$ nuclei are $5.60 \, MeV$ and $7.06 \, MeV$ respectively,then the energy released in the reaction $_3{Li}^7 + _1H^1 \rightarrow 2 \, _2{He}^4$ is ...... $MeV$.

The binding energy per nucleon versus mass number curve is shown in the figure. $W, X, Y$ and $Z$ are four nuclei on the curve. In which process is energy released?

The mass of an $\alpha$-particle is . . . . . . .

The equivalent energy of a mass equal to $1 \, a.m.u.$ is

$A$ nucleus of mass $M$ emits a $\gamma$-ray photon of frequency $\nu$. The loss of internal energy by the nucleus is:

Nucleus $A$ having $Z=17$ and an equal number of protons and neutrons has $1.2 \, MeV$ binding energy per nucleon. Another nucleus $B$ of $Z=12$ has a total of $26$ nucleons and $1.8 \, MeV$ binding energy per nucleon. The difference in binding energy of $B$ and $A$ will be $........... \, MeV$.