In a Coolidge tube,the potential difference between the cathode and the anode is $120 \, kV$. What will be the maximum energy of the emitted $X$-rays?

  • A
    $1.2 \times 10^5 \, eV$
  • B
    $10^{10} \, eV$
  • C
    $10^{15} \, eV$
  • D
    $10^{20} \, eV$

Explore More

Similar Questions

The difference between $\lambda_{K_{\alpha}}$ and $\lambda_{min}$ becomes twice if the accelerating potential changes from $3100 \ V$ to $12400 \ V$. Find $\lambda_{K_{\alpha}}$ in $\mathring{A}$. (Given $hc = 12400 \ eV \mathring{A}$)

In an $X-ray$ tube, the voltage is $5 \, kV$ and the current is $3.2 \, mA$. The number of electrons striking the anode per second is:

The shortest wavelength emitted from an $X$-ray tube depends on which of the following?

$X-$rays are in nature similar to

The wavelengths of $K_{\alpha}$ $X$-rays of two metals $A$ and $B$ are $\frac{4}{1875R}$ and $\frac{1}{675R}$ respectively,where $R$ is Rydberg's constant. The number of elements lying between $A$ and $B$ according to their atomic numbers is

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo