In a hydrogen atom,a transition from n = 4 to | vedclass

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(B) The energy of a photon emitted during a transition between energy levels $n_i$ and $n_f$ is given by $\Delta E = 13.6 \left( \frac{1}{n_f^2} - \fr

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$5 \rightarrow 4$

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(B) The energy of a photon emitted during a transition between energy levels $n_i$ and $n_f$ is given by $\Delta E = 13.6 \left( \frac{1}{n_f^2} - \frac{1}{n_i^2} ight) 	ext{ eV}$.Infrared radiation corresponds to the Paschen series $(n_f = 3)$,Brackett series $(n_f = 4)$,or Pfund series $(n_f = 5)$.The transition from $n = 4$ to $n = 3$ belongs to the Paschen series,which lies in the infrared region.Among the given options,the transition $5 ightarrow 4$ belongs to the Brackett series,which also lies in the infrared region.Therefore,the correct transition is $5 ightarrow 4$.

In a hydrogen atom,a transition from $n = 4$ to $n = 3$ results in the emission of an infrared photon. Which of the following transitions would also result in the emission of an infrared photon?

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