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(C) According to the ideal gas law,the pressure of a gas in a container of volume $V$ at temperature $T$ is given by $P = \frac{N k_B T}{V}$,where $N$

Vedclass · Accepted Answer

$P = P_1 + P_2 + P_3$

Vedclass · Answer

(C) According to the ideal gas law,the pressure of a gas in a container of volume $V$ at temperature $T$ is given by $P = \frac{N k_B T}{V}$,where $N$ is the number of molecules and $k_B$ is the Boltzmann constant.For the three individual containers,we have:$P_1 = \frac{N_1 k_B T}{V}$,$P_2 = \frac{N_2 k_B T}{V}$,and $P_3 = \frac{N_3 k_B T}{V}$.When these gases are mixed into a single container of the same volume $V$ at the same temperature $T$,the total number of molecules becomes $N_{total} = N_1 + N_2 + N_3$.The pressure of the mixture $P$ is given by:$P = \frac{(N_1 + N_2 + N_3) k_B T}{V}$$P = \frac{N_1 k_B T}{V} + \frac{N_2 k_B T}{V} + \frac{N_3 k_B T}{V}$$P = P_1 + P_2 + P_3$.Thus,the pressure of the mixture is the sum of the individual pressures.

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