When boiling water converts into steam,what i | vedclass

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(B) The process of converting boiling water into steam is a phase change process occurring at a constant temperature (isothermal process).For any subs

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$\infty$

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(B) The process of converting boiling water into steam is a phase change process occurring at a constant temperature (isothermal process).For any substance,the specific heat capacity $s$ is defined by the formula:$Q = ms \Delta T$Rearranging for $s$,we get:$s = \frac{Q}{m \Delta T}$In a phase change process,the temperature remains constant,so the change in temperature $\Delta T = 0$.Substituting $\Delta T = 0$ into the formula:$s = \frac{Q}{m 	imes 0} = \infty$Therefore,the specific heat of water during the phase change from liquid to steam is infinite.

Column-$I$	Column-$II$
$A$. Conversion of liquid into solid is	$1$. Regelation
$B$. Conversion of liquid into vapour is	$2$. Sublimation
$C$. Conversion of solid into vapour directly is	$3$. Fusion
$D$. Melting of ice caused by pressure is	$4$. Vaporisation

Column-$I$	Column-$II$
$(a)$ Latent heat of vaporization $L_V$	$(i)$ $22.6 \times 10^5 \, J/kg$
$(b)$ Latent heat of fusion $L_f$	$(ii)$ $33.3 \times 10^5 \, J/kg$
	$(iii)$ $3.33 \times 10^5 \, J/kg$

When boiling water converts into steam,what is the specific heat of water at this state?

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