For a gas,$R/C_V = 0.67$. What kind of molecules is this gas made of?

Obtain the value of $\frac{C_{P}}{C_{V}}$ for a polyatomic gas.

If $C_{p}$ and $C_{v}$ are molar specific heats of an ideal gas at constant pressure and volume respectively and $\gamma$ is $C_{p} / C_{v}$,then $C_{p} =$ (where $R$ is the universal gas constant).

The specific heat at constant volume for the monoatomic argon is $0.075 \, kcal/kg-K$,whereas its gram molecular specific heat $C_V = 2.98 \, cal/mole/K$. The mass of the argon atom is (Avogadro's number $= 6.02 \times 10^{23} \, molecules/mole$)

If the degree of freedom of a gas is $f,$ then the ratio of two specific heats ${C_P}/{C_V}$ is given by

The figure shows the variation in heat supplied $(Q)$ with the change in temperature $(\Delta T)$ in an isobaric process for a monoatomic $(M)$,diatomic $(D)$,and a polyatomic $(P)$ gas. The initial state of all the gases is the same,and the scales for the two axes coincide. Ignoring vibrational degrees of freedom,the lines $a, b,$ and $c$ respectively correspond to