How does the $rms$ velocity of an ideal gas vary with density at constant pressure?

  • A
    $2d$
  • B
    $1/d$
  • C
    $\sqrt{d}$
  • D
    $\frac{1}{\sqrt{d}}$

Explore More

Similar Questions

The value closest to the thermal velocity of a Helium atom at room temperature $(300\,K)$ in $m/s$ is $[k_B = 1.4 \times 10^{-23}\,J/K; m_{He} = 7 \times 10^{-27}\,kg]$.

An ideal gas in a closed container is heated so that the final rms speed of the gas particles increases by $2$ times the initial rms speed. If the initial gas temperature is $27^{\circ} C$,then the final temperature of the ideal gas is : (in $^{\circ} C$)

The temperature of a gas is $-73^{\circ}C$. To what temperature should the gas be heated so that the $rms$ speed of the molecules is doubled (in $^{\circ}C$)?

$A$ tube is divided into two parts,containing two different ideal gases,$L$ and $R$. If the $rms$ velocity of the gas on the left side is equal to the average velocity of the gas on the right side,what is the ratio of the masses of the molecules in $L$ and $R$?

Difficult
View Solution

Let $\bar{v}$,$v_{rms}$ and $v_p$ respectively denote the mean speed,root mean square speed and most probable speed of the molecules in an ideal monoatomic gas at absolute temperature $T$. The mass of the molecule is $m$. Then:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo