A car wheel rotates at 1200 revolutions per m | vedclass

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(D) Initial angular velocity $\omega_1 = 1200 \ rpm = \frac{1200 	imes 2\pi}{60} \ rad/s = 40\pi \ rad/s$. Final angular velocity $\omega_2 = 4500 \

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$1980 \ deg/s^2$

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(D) Initial angular velocity $\omega_1 = 1200 \ rpm = \frac{1200 	imes 2\pi}{60} \ rad/s = 40\pi \ rad/s$. Final angular velocity $\omega_2 = 4500 \ rpm = \frac{4500 	imes 2\pi}{60} \ rad/s = 150\pi \ rad/s$. Time interval $\Delta t = 10 \ s$. Angular acceleration $\alpha = \frac{\omega_2 - \omega_1}{\Delta t} = \frac{150\pi - 40\pi}{10} = \frac{110\pi}{10} = 11\pi \ rad/s^2$. To convert to degrees per second squared $(deg/s^2)$,multiply by $\frac{180}{\pi}$: $\alpha = 11\pi 	imes \frac{180}{\pi} = 11 	imes 180 = 1980 \ deg/s^2$.

$A$ car wheel rotates at $1200$ revolutions per minute. On pressing the accelerator,it rotates at $4500$ revolutions per minute in $10 \ s$. The angular acceleration of the wheel is ...

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