When a particle is moving in a circular path | vedclass

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(D) The angular momentum $\vec{L}$ of a particle is defined by the cross product $\vec{L} = \vec{r} 	imes \vec{p} = \vec{r} 	imes (m\vec{v})$.Since

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Along the axis of rotation

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(D) The angular momentum $\vec{L}$ of a particle is defined by the cross product $\vec{L} = \vec{r} 	imes \vec{p} = \vec{r} 	imes (m\vec{v})$.Since the position vector $\vec{r}$ lies in the plane of rotation and the linear velocity vector $\vec{v}$ is tangent to the circular path (also in the plane of rotation),the cross product $\vec{r} 	imes \vec{v}$ results in a vector perpendicular to both $\vec{r}$ and $\vec{v}$.By the right-hand rule,this direction is perpendicular to the plane of rotation,which corresponds to the axis of rotation.

When a particle is moving in a circular path around a fixed point in a plane,the direction of its angular momentum is ........

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