In the figure (a),half of the meter scale is | vedclass

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(B) The torque $	au$ applied in both cases is $	au = r 	imes F$,which is the same since the distance $r$ from the pivot to the point of application

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More angular acceleration will be produced in $(b)$.

Vedclass · Answer

(B) The torque $	au$ applied in both cases is $	au = r 	imes F$,which is the same since the distance $r$ from the pivot to the point of application of force is the same in both cases.According to the rotational analogue of Newton's second law,$	au = I \alpha$,where $I$ is the moment of inertia and $\alpha$ is the angular acceleration.Therefore,$\alpha = \frac{	au}{I}$.Since the density of steel is greater than that of wood,the mass of the steel part is greater than the mass of the wooden part.In case $(a)$,the heavier steel part is further from the pivot $O$,resulting in a larger moment of inertia $I_a$.In case $(b)$,the heavier steel part is closer to the pivot $O'$,resulting in a smaller moment of inertia $I_b$.Since $I_a > I_b$,it follows that $\alpha_b > \alpha_a$.Thus,more angular acceleration will be produced in $(b)$.

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