When 10 g of glucose (P_1),10 g of urea (P_ | vedclass

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(C) Osmotic pressure $(\Pi)$ is given by the formula $\Pi = CRT = \frac{n}{V}RT = \frac{w}{M 	imes V}RT$. Since $w$ (mass),$V$ (volume),$R$ (gas cons

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$P_2 > P_1 > P_3$

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(C) Osmotic pressure $(\Pi)$ is given by the formula $\Pi = CRT = \frac{n}{V}RT = \frac{w}{M 	imes V}RT$. Since $w$ (mass),$V$ (volume),$R$ (gas constant),and $T$ (temperature) are constant for all three solutions,the osmotic pressure is inversely proportional to the molar mass $(M)$ of the solute: $\Pi \propto \frac{1}{M}$. The molar masses are: Urea $(NH_2CONH_2)$ = $60 \ g/mol$,Glucose $(C_6H_{12}O_6)$ = $180 \ g/mol$,and Sucrose $(C_{12}H_{22}O_{11})$ = $342 \ g/mol$. Since $60  P_1 > P_3$.

When $10 \ g$ of glucose $(P_1)$,$10 \ g$ of urea $(P_2)$,and $10 \ g$ of sucrose $(P_3)$ are dissolved in $250 \ mL$ of water,what is the relationship between their osmotic pressures at $273 \ K$?

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