What is the approximate normality of a 10% (W | vedclass

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(D) The concentration is given as $10\% (W/V)$,which means $10 \ g$ of $H_2SO_4$ is present in $100 \ mL$ of the solution.Normality $(N)$ is defined a

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$2$

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(D) The concentration is given as $10\% (W/V)$,which means $10 \ g$ of $H_2SO_4$ is present in $100 \ mL$ of the solution.Normality $(N)$ is defined as the number of gram equivalents of solute per liter of solution.$N = \frac{	ext{Mass of solute in } g}{	ext{Equivalent mass of solute} 	imes 	ext{Volume of solution in } L}$.The molar mass of $H_2SO_4$ is $98 \ g/mol$. Since it is a dibasic acid,its n-factor is $2$.Equivalent mass of $H_2SO_4 = \frac{98}{2} = 49 \ g/eq$.Volume of solution = $100 \ mL = 0.1 \ L$.$N = \frac{10 \ g}{49 \ g/eq 	imes 0.1 \ L} = \frac{10}{4.9} \approx 2.04 \ N$.Therefore,the approximate normality is $2$.

What is the approximate normality of a $10\% (W/V)$ $H_2SO_4$ solution?

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