If the van't Hoff factor of a weak electrolyt | vedclass

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Question

(A) For the dissociation of a weak electrolyte $A_xB_y$: $A_xB_y \rightleftharpoons xA^{y+} + yB^{x-}$ Initial moles: $1, 0, 0$ Moles at equilibrium:

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$\alpha = \frac{i - 1}{x + y - 1}$

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(A) For the dissociation of a weak electrolyte $A_xB_y$: $A_xB_y ightleftharpoons xA^{y+} + yB^{x-}$ Initial moles: $1, 0, 0$ Moles at equilibrium: $(1 - \alpha), x\alpha, y\alpha$ Total moles at equilibrium = $(1 - \alpha) + x\alpha + y\alpha = 1 + \alpha(x + y - 1)$ Van't Hoff factor $i = \frac{	ext{Total moles at equilibrium}}{	ext{Initial moles}} = 1 + \alpha(x + y - 1)$ $i - 1 = \alpha(x + y - 1)$ $\alpha = \frac{i - 1}{x + y - 1}$

If the van't Hoff factor of a weak electrolyte $A_xB_y$ is $i$,then the degree of dissociation $(\alpha)$ is represented by which equation?

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