An aqueous solution of urea (molar mass 60 g | vedclass

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(A) $1$. Calculate the molality $(m)$ of the solution using the elevation in boiling point formula: $\Delta T_b = K_b 	imes m$. $2$. Given $\Delta T_

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$272.73$

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(A) $1$. Calculate the molality $(m)$ of the solution using the elevation in boiling point formula: $\Delta T_b = K_b 	imes m$. $2$. Given $\Delta T_b = 100.18 - 100 = 0.18 \ K$ and $K_b = 0.512 \ K \ kg \ mol^{-1}$. $3$. $m = \frac{\Delta T_b}{K_b} = \frac{0.18}{0.512} \approx 0.3516 \ mol \ kg^{-1}$. $4$. Calculate the depression in freezing point: $\Delta T_f = K_f 	imes m$. $5$. $\Delta T_f = 1.86 	imes 0.3516 \approx 0.654 \ K$. $6$. The freezing point of the solution is $T_f = T_f^\circ - \Delta T_f = 273.15 \ K - 0.654 \ K = 272.496 \ K \approx 272.50 \ K$. $7$. Based on the calculation,the closest option is $272.73 \ K$ (noting potential rounding differences in standard problems).

An aqueous solution of urea (molar mass $60 \ g \ mol^{-1}$) boils at $100.18 \ ^\circ C$ at $1 \ atm$ pressure. If $K_f$ and $K_b$ for water are $1.86$ and $0.512 \ K \ kg \ mol^{-1}$ respectively,at what temperature will this solution freeze (in $K$)?

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Which of the following statements concerning the properties of solutions describes a colligative effect?

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Assertion : If one component of a solution obeys Raoult's law over a certain range of composition,the other component will not obey Henry's law in that range.
Reason : Raoult's law is a special case of Henry's law.

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