The position vectors of two particles of mass | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The position vector of the center of mass $\vec{r}_{cm}$ is given by the formula: $\vec{r}_{cm} = \frac{m_1\vec{r}_1 + m_2\vec{r}_2}{m_1 + m_2}$.G

Vedclass · Accepted Answer

$-2\hat{i} - \hat{j} + \hat{k}$

Vedclass · Answer

(B) The position vector of the center of mass $\vec{r}_{cm}$ is given by the formula: $\vec{r}_{cm} = \frac{m_1\vec{r}_1 + m_2\vec{r}_2}{m_1 + m_2}$.Given: $m_1 = 1 \, kg$,$\vec{r}_1 = \hat{i} + 2\hat{j} + \hat{k}$ and $m_2 = 3 \, kg$,$\vec{r}_2 = -3\hat{i} - 2\hat{j} + \hat{k}$.Substituting the values: $\vec{r}_{cm} = \frac{1(\hat{i} + 2\hat{j} + \hat{k}) + 3(-3\hat{i} - 2\hat{j} + \hat{k})}{1 + 3}$.$\vec{r}_{cm} = \frac{\hat{i} + 2\hat{j} + \hat{k} - 9\hat{i} - 6\hat{j} + 3\hat{k}}{4}$.$\vec{r}_{cm} = \frac{-8\hat{i} - 4\hat{j} + 4\hat{k}}{4}$.$\vec{r}_{cm} = -2\hat{i} - \hat{j} + \hat{k}$.

The position vectors of two particles of masses $1 \, kg$ and $3 \, kg$ are $\hat{i} + 2\hat{j} + \hat{k}$ and $-3\hat{i} - 2\hat{j} + \hat{k}$ respectively. The position vector of the center of mass of the system of these particles is:

Similar Questions

$A$ convex lens of focal length $0.15 \ m$ is made of a material of refractive index $\frac{3}{2}$. When it is placed in a liquid,its focal length increases by $0.225 \ m$. The refractive index of the liquid is

During embryonic development,the establishment of polarity along the anterior/posterior,dorsal/ventral,or medial/lateral axis is called:

Which of the following is $NOT$ included in in-situ conservation?

What product is obtained from the reaction of a Grignard reagent with a ketone?

The major product of the following reaction is

Vedclass Test Series

Exam Paper Generator

Online Exam Module