(C) For a one-dimensional elastic collision where the second body is initially at rest,the fraction of kinetic energy retained by the first body (mass

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(C) For a one-dimensional elastic collision where the second body is initially at rest,the fraction of kinetic energy retained by the first body (mass $m_1$) after the collision is given by the formula: $f = \left( \frac{m_1 - m_2}{m_1 + m_2} \right)^2$ Given $m_1 = 8 \ kg$ and $m_2 = 2 \ kg$. Substituting the values: $f = \left( \frac{8 - 2}{8 + 2} \right)^2 = \left( \frac{6}{10} \right)^2 = (0.6)^2 = 0.36$. Therefore,the remaining kinetic energy is $0.36 E$.

Class 11 Physics Work, Energy, Power and Collision Elastic Collision

Medium

$A$ body of mass $8 \ kg$ moving with a certain velocity collides elastically with another body of mass $2 \ kg$ at rest. If $E$ is the initial kinetic energy of the moving mass,what will be the remaining kinetic energy of the moving mass after the collision (in $E$)?

A
$0.80$
B
$0.64$
C
$0.36$
D
$0.08$

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Work, Energy, Power and Collision

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Elastic Collision

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$A$ body of mass $8 \ kg$ moving with a certain velocity collides elastically with another body of mass $2 \ kg$ at rest. If $E$ is the initial kinetic energy of the moving mass,what will be the remaining kinetic energy of the moving mass after the collision (in $E$)?

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$A$ sphere of mass $0.1 \ kg$ is attached to a string of length $1 \ m$. It is released from a horizontal position and collides with another sphere of equal mass $m$ at rest. Find the kinetic energy gained by the second sphere. The collision is perfectly elastic. (in $J$)

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