A metal ball hits a wall and does not rebound | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the mass of the balls be $m$ and the initial velocity be $v_1$. For the metal ball,the final velocity $v_2 = 0$ (as it does not rebound). The

Vedclass · Accepted Answer

The rubber ball experiences a greater change in momentum.

Vedclass · Answer

(B) Let the mass of the balls be $m$ and the initial velocity be $v_1$. For the metal ball,the final velocity $v_2 = 0$ (as it does not rebound). The change in momentum is $\Delta p = m(v_2 - v_1) = m(0 - v_1) = -mv_1$. The magnitude of change is $|\Delta p| = mv_1$. For the rubber ball,the final velocity $v_2' = -v_1$ (as it rebounds with the same velocity). The change in momentum is $\Delta p' = m(v_2' - v_1) = m(-v_1 - v_1) = -2mv_1$. The magnitude of change is $|\Delta p'| = 2mv_1$. Comparing the two,$|\Delta p'| > |\Delta p|$. Therefore,the rubber ball experiences a greater change in momentum.

$A$ metal ball hits a wall and does not rebound,whereas a rubber ball of the same mass hits the wall with the same velocity and rebounds. What can be concluded from this?

Similar Questions

Two bodies $A$ and $B$ collide as shown in Fig. $(i)$ and $(ii)$. Which statement is true?

$A$ force-time $(F-t)$ graph for a linear motion is shown in the following figure. The segments shown are circular. The linear momentum gained between $0$ and $8 \,s$ is

Action and reaction forces act on

$A$ body of mass $2 \ kg$ has an initial speed of $5 \ ms^{-1}$. $A$ force acts on it for some time in the direction of motion. The force-time graph is shown in the figure. The final speed of the body is .......... $ms^{-1}$.

$Assertion$ : $A$ quick collision between two bodies is more violent than a slow collision,even when the initial and final velocities are identical.
$Reason$ : The rate of change of momentum is greater in the first case.

Vedclass Test Series

Exam Paper Generator

Online Exam Module