For the equilibrium C_{(diamond)} rightleftha | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Le Chatelier's principle,increasing the pressure favors the direction in which the volume decreases (or density increases). Density i

Vedclass · Accepted Answer

The backward reaction is favored.

Vedclass · Answer

(A) According to Le Chatelier's principle,increasing the pressure favors the direction in which the volume decreases (or density increases). Density is defined as $	ext{Density} = \frac{	ext{Mass}}{	ext{Volume}}$,which implies $	ext{Volume} = \frac{	ext{Mass}}{	ext{Density}}$. Since the density of diamond $(3.5 \ g/mL)$ is greater than that of graphite $(2.3 \ g/mL)$,the volume of $1 \ g$ of diamond is less than the volume of $1 \ g$ of graphite. Therefore,increasing the pressure shifts the equilibrium towards the side with the smaller volume,which is the diamond side. Thus,the backward reaction is favored.

For the equilibrium $C_{(diamond)} \rightleftharpoons C_{(graphite)}$,the densities of diamond and graphite are $3.5 \ g/mL$ and $2.3 \ g/mL$ respectively. What happens to the equilibrium upon increasing the pressure?

Similar Questions

Under which conditions of temperature and pressure is the dissociation of molecular hydrogen into atomic hydrogen favored?

In what manner will an increase of pressure affect the following equilibrium equation?
$C_{(s)} + H_2O_{(g)} \rightleftharpoons CO_{(g)} + H_{2(g)}$

The reaction $2SO_2 + O_2 \rightleftharpoons 2SO_3$; $\Delta H = -ve$ is favoured by

When pressure is applied to the system $Ice \rightleftharpoons Water$,what will happen?

For a reaction,the value of $K_p$ increases with an increase in temperature. The $\Delta H$ for the reaction would be

Vedclass Test Series

Exam Paper Generator

Online Exam Module