For a reversible reaction involving two reactants,if the concentration of the reactants is doubled,the equilibrium constant will:

  • A
    Double
  • B
    Become half
  • C
    Become one-fourth
  • D
    Remain the same

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Similar Questions

In which of the following reactions,the concentration of product is higher than the concentration of reactant at equilibrium? $(K = \text{equilibrium constant})$

For the reaction ${H_{2(g)} + I_{2(g)} \rightleftharpoons 2HI_{(g)}}$,the equilibrium constant $K_p$ changes with the change in:

At what change in Gibbs free energy $(\Delta G)$ does a reaction reach equilibrium?

If the equilibrium constant of a reaction is $K_c = 1.6 \times 10^{12}$,then at equilibrium,the system will contain:

If the concentration of reactants is increased by $x$,then the equilibrium constant $K$ becomes:

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