For the reaction $PCl_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)}$,the forward reaction is favored at constant temperature by: $(1)$ Adding an inert gas at constant volume $(2)$ Adding $Cl_{2(g)}$ at constant volume $(3)$ Adding an inert gas at constant pressure $(4)$ Increasing the volume of the container $(5)$ Adding $PCl_{5(g)}$ at constant volume

  • A
    $(1), (2), (3)$
  • B
    $(2), (3), (4)$
  • C
    $(3), (4), (5)$
  • D
    $(1), (3), (4), (5)$

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In which of the following reactions at equilibrium,the position of the equilibrium shifts towards the products,if the total pressure is increased?
$(I)$ $X_{2(g)} + 3Y_{2(g)} \rightleftharpoons 2XY_{3(g)}$
$(II)$ $X_{2(g)} + Y_{2(g)} \rightleftharpoons 2XY_{(g)}$
$(III)$ $X_{2(g)} + Z_{2(g)} \rightleftharpoons 2XZ_{(g)}$
$(IV)$ $X_{2(g)} + Y_{4(g)} \rightleftharpoons 2XY_{2(g)}$

The $\%$ yield of ammonia as a function of time in the reaction $N_{2(g)} + 3H_{2(g)} \rightleftharpoons 2NH_{3(g)}$,$\Delta H < 0$ at $(P, T_1)$ is given below. If this reaction is conducted at $(P, T_2)$,with $T_2 > T_1$,the $\%$ yield of ammonia as a function of time is represented by:

When an orange solution containing $Cr_{2}O_{7}^{2-}$ ions is treated with an alkali,a yellow solution is formed,and when $H^{+}$ ions are added to the yellow solution,an orange solution is obtained. Explain why this happens.

Match List-$I$ (Equilibrium) with List-$II$ (Conditions for the process) and select the correct answer from the options given below.
List-$I$ (Equilibrium) List-$II$ (Conditions for the process)
$P. A_{2(g)} + B_{2(g)} \rightleftharpoons 2AB_{(g)}$ (Endothermic) $1. \text{High temperature}$
$Q. 2AB_{2(g)} + B_{2(g)} \rightleftharpoons 2AB_{3(g)}$ (Exothermic) $2. \text{Low temperature}$
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$4. \text{Low temperature}$
$5. \text{Independent of pressure}$

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