If the solubility product of AgCl is 10^{-10} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The dissociation of $AgCl$ is: $AgCl(s) ⇌ Ag^+(aq) + Cl^-(aq)$.Let the solubility of $AgCl$ be $s \ mol/L$.$NaCl$ is a strong electrolyte and diss

Vedclass · Accepted Answer

$10^{-7}$

Vedclass · Answer

(D) The dissociation of $AgCl$ is: $AgCl(s) ⇌ Ag^+(aq) + Cl^-(aq)$.Let the solubility of $AgCl$ be $s \ mol/L$.$NaCl$ is a strong electrolyte and dissociates completely: $NaCl(aq) → Na^+(aq) + Cl^-(aq)$.Concentration of $Cl^-$ from $NaCl$ is $0.001 \ M$.Total concentration of $[Cl^-] = (s + 0.001) \ M \approx 0.001 \ M$ (since $s$ is very small).$K_{sp} = [Ag^+][Cl^-] = s 	imes 0.001 = 10^{-10}$.$s = \frac{10^{-10}}{10^{-3}} = 10^{-7} \ M$.

If the solubility product of $AgCl$ is $10^{-10}$,what is the solubility of $AgCl$ in $0.001 \ M \ NaCl$?

Similar Questions

Which of the following substances is insoluble in dilute hydrochloric acid?

If '$s$' and '$S$' are the solubility and solubility product of a sparingly soluble binary electrolyte respectively,then which of the following relations is correct?

The solubility product of a sparingly soluble salt $AX_2$ is $3.2 \times 10^{-11}$. Its solubility in $mol/L$ is:

The solubility of $AgCl_{(s)}$ with solubility product $1.6 \times 10^{-10}$ in $0.1 \ M \ NaCl$ solution would be

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$CaSO_3 \downarrow + SO_2 + H_2O \longrightarrow Ca(HSO_3)_2$

Vedclass Test Series

Exam Paper Generator

Online Exam Module