Under which condition does a basic buffer fol | vedclass

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(C) The Henderson-Hasselbalch equation for a basic buffer is given by: $pOH = pK_b + log \frac{[	ext{Conjugate Acid}]}{[	ext{Base}]}$ Given the equa

Vedclass · Accepted Answer

$[	ext{Conjugate Acid}] : [	ext{Base}] = 10 : 1$

Vedclass · Answer

(C) The Henderson-Hasselbalch equation for a basic buffer is given by: $pOH = pK_b + log \frac{[	ext{Conjugate Acid}]}{[	ext{Base}]}$ Given the equation: $pOH - pK_b = 1$ Substituting this into the Henderson-Hasselbalch equation: $1 = log \frac{[	ext{Conjugate Acid}]}{[	ext{Base}]}$ Taking the antilog on both sides: $10^1 = \frac{[	ext{Conjugate Acid}]}{[	ext{Base}]}$ Therefore,$\frac{[	ext{Conjugate Acid}]}{[	ext{Base}]} = 10$ This implies the ratio $[	ext{Conjugate Acid}] : [	ext{Base}] = 10 : 1$.

Under which condition does a basic buffer follow the equation $pOH - pK_b = 1$?

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