(C) Lewis acid is defined as an electron pair acceptor.$SO_3$ (sulfur trioxide) has an electron-deficient sulfur atom that can accept a lone pair of e

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(C) Lewis acid is defined as an electron pair acceptor.$SO_3$ (sulfur trioxide) has an electron-deficient sulfur atom that can accept a lone pair of electrons from a base.$CaO$ is a basic oxide.$CH_3NH_2$ (methylamine) acts as a Lewis base because it has a lone pair of electrons on the nitrogen atom.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)Acids and Bases

Easy

Which of the following is an example of a Lewis acid?

A
$CaO$
B
$CH_3NH_2$
C
$SO_3$
D
None of these

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Class 11

Chemistry Questions

Chapter

6-2.Equilibrium-II (Ionic Equilibrium)

Subtopic

Acids and Bases

Match the following acids in List-$I$ with their respective acid dissociation constants $(K_a)$ in List-$II$:
List-$I$ (Acid) List-$II$ $(K_a)$
$A$. Phenol $I$. $1 \times 10^{-13}$
$B$. Benzoic acid $II$. $3.0 \times 10^{-8}$
$C$. $HClO$ $III$. $1.0 \times 10^{-10}$
$D$. $CH_3COOH$ $IV$. $6.5 \times 10^{-5}$
$V$. $1.75 \times 10^{-5}$

The correct match is:

List-$I$ (Acid)	List-$II$ $(K_a)$
$A$. Phenol	$I$. $1 \times 10^{-13}$
$B$. Benzoic acid	$II$. $3.0 \times 10^{-8}$
$C$. $HClO$	$III$. $1.0 \times 10^{-10}$
$D$. $CH_3COOH$	$IV$. $6.5 \times 10^{-5}$
	$V$. $1.75 \times 10^{-5}$