Which of the following equations is correct f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For the dissociation of ammonium chloride: $NH_4Cl(s) \rightleftharpoons NH_3(g) + HCl(g)$.Here,the number of moles of gaseous products $n = 2$.Th

Vedclass · Accepted Answer

$D_o = \frac{D_t}{2}$

Vedclass · Answer

(C) For the dissociation of ammonium chloride: $NH_4Cl(s) \rightleftharpoons NH_3(g) + HCl(g)$.Here,the number of moles of gaseous products $n = 2$.The relationship between degree of dissociation $(x)$,theoretical vapour density $(D_t)$,and observed vapour density $(D_o)$ is given by: $x = \frac{D_t - D_o}{D_o(n - 1)}$.For complete dissociation,$x = 1$ and $n = 2$.Substituting these values: $1 = \frac{D_t - D_o}{D_o(2 - 1)}$.$1 = \frac{D_t - D_o}{D_o} \implies D_o = D_t - D_o \implies 2D_o = D_t$.Therefore,$D_o = \frac{D_t}{2}$.

Which of the following equations is correct for the vapour density of completely dissociated ammonium chloride?

Similar Questions

What is the vapour density of $O_2$ gas?

For a $10^{-2} \ M \ HCN$ solution with $[H^+] = 10^{-3} \ M$,find the value of the degree of dissociation in percentage. (in $\%$)

In a $100 \ L$ vessel,$3 \ moles$ of nitrogen and $3 \ moles$ of $PCl_5$ are taken and heated to $500 \ K$. The equilibrium pressure is $3.28 \ atm$. The percentage degree of dissociation of $PCl_5$ is : (Assume ideal behaviour for all gases).

The equilibrium constant at a certain temperature for the reaction $A_2 + B_2 \rightleftharpoons 2AB$ is $2$. Calculate the degree of dissociation of either $A_2$ or $B_2$.

Consider the following gas phase dissociation,$PCl_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)}$ with equilibrium constant $K_P$ at a particular temperature and at pressure $P$. The degree of dissociation $(\alpha)$ for $PCl_{5(g)}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module