For which sparingly soluble salt is the relat | vedclass

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Question

(C) For a salt of the type $AB_2$,the dissociation is $AB_2 \rightleftharpoons A^{2+} + 2B^-$. If solubility is $S$,then $[A^{2+}] = S$ and $[B^-] = 2

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$Hg_2Cl_2$

Vedclass · Answer

(C) For a salt of the type $AB_2$,the dissociation is $AB_2 \rightleftharpoons A^{2+} + 2B^-$. If solubility is $S$,then $[A^{2+}] = S$ and $[B^-] = 2S$. $K_{sp} = [A^{2+}][B^-]^2 = (S)(2S)^2 = 4S^3$. Therefore,$S^3 = K_{sp} / 4$,which gives $S = (K_{sp} / 4)^{1/3}$. Among the given options,$Hg_2Cl_2$ dissociates as $Hg_2Cl_2 \rightleftharpoons Hg_2^{2+} + 2Cl^-$,which follows the $AB_2$ type stoichiometry. Thus,the correct option is $C$.

For which sparingly soluble salt is the relationship between $K_{sp}$ and $S$ (solubility) given by $S = (K_{sp} / 4)^{1/3}$?

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