What is the solubility of Ag_2CO_3 in 0.1 , M | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The solubility equilibrium for $Ag_2CO_3$ is: $Ag_2CO_3(s) \rightleftharpoons 2Ag^+(aq) + CO_3^{2-}(aq)$.Given $K_{sp} = [Ag^+]^2 [CO_3^{2-}] = 4

Vedclass · Accepted Answer

$10^{-6}$

Vedclass · Answer

(A) The solubility equilibrium for $Ag_2CO_3$ is: $Ag_2CO_3(s) ightleftharpoons 2Ag^+(aq) + CO_3^{2-}(aq)$.Given $K_{sp} = [Ag^+]^2 [CO_3^{2-}] = 4 	imes 10^{-13}$.In the presence of $0.1 \, M \, Na_2CO_3$,the concentration of $CO_3^{2-}$ is approximately $0.1 \, M$ due to the common ion effect.Let $s$ be the solubility of $Ag_2CO_3$. Then $[Ag^+] = 2s$ and $[CO_3^{2-}] \approx 0.1$.Substituting these into the $K_{sp}$ expression: $4 	imes 10^{-13} = (2s)^2 (0.1)$.$4 	imes 10^{-13} = 4s^2 	imes 0.1$.$s^2 = \frac{4 	imes 10^{-13}}{4 	imes 0.1} = 10^{-12}$.$s = \sqrt{10^{-12}} = 10^{-6} \, M$.

What is the solubility of $Ag_2CO_3$ in $0.1 \, M \, Na_2CO_3$? The solubility product $(K_{sp})$ of $Ag_2CO_3$ at the same temperature is $4 \times 10^{-13}$.

Similar Questions

When $H_2S$ is passed through a solution containing $HCl$ for qualitative analysis,it does not precipitate group $IV$ cations. Why is this?

In the presence of $HCl$,$H_2S$ results in the precipitation of Group-$2$ elements but not Group-$4$ elements during qualitative analysis. It is due to

Assertion : $Sb_2S_3$ is not soluble in yellow ammonium sulphide. Reason : The common ion effect due to $S^{2-}$ ions reduces the solubility of $Sb_2S_3$.

If the maximum concentration of $PbCl_2$ in water at $298 \, K$ is $0.01 \, M$,what is its maximum concentration in $0.1 \, M \, NaCl$ solution?

In the Solvay ammonia process,what causes the precipitation of sodium bicarbonate?

Vedclass Test Series

Exam Paper Generator

Online Exam Module