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(A) The molar mass of $CaCO_3$ is $40 + 12 + (3 	imes 16) = 100 \ g/mol$. Given mass of residue = $7.0 \ g$ in $1 \ L$ of solution. Solubility $(S)$

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$4.9 	imes 10^{-3}$

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(A) The molar mass of $CaCO_3$ is $40 + 12 + (3 	imes 16) = 100 \ g/mol$. Given mass of residue = $7.0 \ g$ in $1 \ L$ of solution. Solubility $(S)$ in $mol/L = \frac{	ext{mass}}{	ext{molar mass}} = \frac{7.0 \ g}{100 \ g/mol} = 0.07 \ mol/L$. For $CaCO_3 ightleftharpoons Ca^{2+} + CO_3^{2-}$,the solubility product $K_{sp} = [Ca^{2+}][CO_3^{2-}] = S 	imes S = S^2$. $K_{sp} = (0.07)^2 = 0.0049 = 4.9 	imes 10^{-3}$.

Evaporation of $1 \ L$ of a saturated solution of $CaCO_3$ leaves a residue of $7.0 \ g$. What is the solubility product $(K_{sp})$ for $CaCO_3$?

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