For a first-order reaction,which of the follo | vedclass

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(A) For a first-order reaction,the integrated rate law is given by $[A]_t = [A]_0 e^{-kt}$.The degree of dissociation (or fraction reacted) $\alpha$ i

Vedclass · Accepted Answer

The degree of dissociation is equal to $(1 - e^{-kt})$.

Vedclass · Answer

(A) For a first-order reaction,the integrated rate law is given by $[A]_t = [A]_0 e^{-kt}$.The degree of dissociation (or fraction reacted) $\alpha$ is given by $\alpha = \frac{[A]_0 - [A]_t}{[A]_0} = 1 - \frac{[A]_t}{[A]_0} = 1 - e^{-kt}$.Thus,option $A$ is correct.In the Arrhenius equation $k = A e^{-E_a/RT}$,the pre-exponential factor $A$ has the same units as the rate constant $k$. For a first-order reaction,the unit of $k$ is $s^{-1}$,which is the reciprocal of time,not time itself. Therefore,option $B$ is incorrect.For a first-order reaction,the plot of $\ln[A]$ versus time is a straight line,not the reciprocal of concentration. Therefore,option $C$ is incorrect.

For a first-order reaction,which of the following statements is correct?

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