According to the adsorption theory of catalysis,the rate of reaction increases because:
- AAdsorption produces energy which increases the rate of reaction.
- BAdsorption lowers the activation energy of the reaction.
- CThe concentration of reactants increases on the active centers of the catalyst due to adsorption.
- DAdsorption increases the activation energy of the molecules in the reaction.
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Similar Questions
What is shape-selective catalysis?
Medium
View SolutionMatch the catalyst given in List-$I$ with the process in List-$II$.
List-$I$ (Catalyst) List-$II$ (Process) $A$. $Ni$ in presence of $H_2$ $1$. Ziegler-Natta catalyst $B$. $Cu_2Cl_2$ $2$. Contact process $C$. $V_2O_5$ $3$. Hydrogenation of vegetable oils $D$. Finely divided iron $4$. Sandmeyer reaction $E$. $TiCl_4 + Al(CH_3)_3$ $5$. Haber process $6$. Decomposition of $KClO_3$
| List-$I$ (Catalyst) | List-$II$ (Process) |
| $A$. $Ni$ in presence of $H_2$ | $1$. Ziegler-Natta catalyst |
| $B$. $Cu_2Cl_2$ | $2$. Contact process |
| $C$. $V_2O_5$ | $3$. Hydrogenation of vegetable oils |
| $D$. Finely divided iron | $4$. Sandmeyer reaction |
| $E$. $TiCl_4 + Al(CH_3)_3$ | $5$. Haber process |
| $6$. Decomposition of $KClO_3$ |
Medium
View SolutionWhich of the following statements is $NOT$ correct?
Easy
View SolutionDescribe how the enthalpy of reaction remains unchanged when a catalyst is used in the reaction.
Easy
View SolutionMatch the following.
List-$I$ (Reaction) List-$II$ (Catalyst) $A$. $N_{2(g)} + 3H_{2(g)} \longrightarrow 2NH_{3(g)}$ $I$. $Ni$ $B$. $2H_{2(g)} + O_{2(g)} \longrightarrow 2H_2O_{(l)}$ $II$. $Pt$ $C$. $CO_{(g)} + 3H_{2(g)} \longrightarrow CH_{4(g)} + H_2O_{(g)}$ $III$. $ZnO-Cr_2O_3$ $D$. $CO_{(g)} + 2H_{2(g)} \longrightarrow CH_3OH_{(g)}$ $IV$. $Fe$
The correct answer is:
| List-$I$ (Reaction) | List-$II$ (Catalyst) |
|---|---|
| $A$. $N_{2(g)} + 3H_{2(g)} \longrightarrow 2NH_{3(g)}$ | $I$. $Ni$ |
| $B$. $2H_{2(g)} + O_{2(g)} \longrightarrow 2H_2O_{(l)}$ | $II$. $Pt$ |
| $C$. $CO_{(g)} + 3H_{2(g)} \longrightarrow CH_{4(g)} + H_2O_{(g)}$ | $III$. $ZnO-Cr_2O_3$ |
| $D$. $CO_{(g)} + 2H_{2(g)} \longrightarrow CH_3OH_{(g)}$ | $IV$. $Fe$ |
The correct answer is:
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