For the decomposition of N_2O_5, the reaction | vedclass

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(C) The activation energy $(E_a)$ is the minimum energy required for a reaction to occur. It is a characteristic property of the reaction mechanism an

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$E_a' = E_a$

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(C) The activation energy $(E_a)$ is the minimum energy required for a reaction to occur. It is a characteristic property of the reaction mechanism and the transition state,which depends on the nature of the reactants and the pathway,not on the stoichiometric coefficients used to balance the chemical equation. When we multiply or divide the stoichiometric coefficients of a balanced chemical equation by a constant factor,the reaction pathway and the transition state remain the same. Therefore,the activation energy $E_a$ remains unchanged regardless of the stoichiometric coefficients. Thus,$E_a = E_a'$.

For the decomposition of $N_2O_5,$ the reaction is $2N_2O_{5(g)} \rightarrow 4NO_{2(g)} + O_{2(g)}$ with activation energy $E_a.$ If the reaction is written as $N_2O_{5(g)} \rightarrow 2NO_{2(g)} + 1/2 O_{2(g)}$ with activation energy $E_a',$ what is the relationship between $E_a$ and $E_a'$?

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