(D) For a first-order reaction,the rate constant $k$ is given by: $k = \frac{2.303}{t} \log \frac{[A]_0}{[A]_t}$ $k = \frac{2.303}{40} \log \frac{0.1}

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$7.50 \times 10^{-4} \, M \, min^{-1}$

(D) For a first-order reaction,the rate constant $k$ is given by: $k = \frac{2.303}{t} \log \frac{[A]_0}{[A]_t}$ $k = \frac{2.303}{40} \log \frac{0.1}{0.005} = \frac{2.303}{40} \log 20$ $k = \frac{2.303 \times 1.3010}{40} \approx 0.0749 \, min^{-1}$ Now,the rate of reaction is given by: $Rate = k[X] = 0.0749 \times 0.01$ $Rate = 7.49 \times 10^{-4} \, M \, min^{-1} \approx 7.50 \times 10^{-4} \, M \, min^{-1}$

Class 12 Chemistry Chemical Kinetics First Order reaction

Difficult

In a first-order reaction,the concentration of reactant $X$ decreases from $0.1 \, M$ to $0.005 \, M$ in $40 \, min$. What will be the rate of reaction when the concentration of $X$ is $0.01 \, M$?

A
$1.73 \times 10^{-4} \, M \, min^{-1}$
B
$3.74 \times 10^{-4} \, M \, min^{-1}$
C
$3.47 \times 10^{-5} \, M \, min^{-1}$
D
$7.50 \times 10^{-4} \, M \, min^{-1}$

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Chemical Kinetics

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First Order reaction

$A$ first-order reaction takes $10 \ hours$ to complete $90\%$ of the reaction. How much time will it take to complete $99.9\%$ of the reaction (in $hours$)?

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For the first-order gaseous reaction $A_{(g)} \to 2B_{(g)} + C_{(g)}$,the expression for the rate constant $K$ in terms of initial pressure $P_0$ and total pressure $P_t$ at time $t$ is:

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If a $75\%$ first-order reaction is completed in $32 \text{ minutes}$,how many minutes will it take for the same reaction to be $50\%$ completed?

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Half-life for a first order reaction is $6.93 \ hour$. What is the time required for $80 \%$ completion of the reaction (in $hours$)?

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$A$ reaction has a rate constant $k = 2.4 \times 10^{-4} \ s^{-1}$. Find the ratio of $t_{99.9}$ to $t_{50}$.

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In a first-order reaction,the concentration of reactant $X$ decreases from $0.1 \, M$ to $0.005 \, M$ in $40 \, min$. What will be the rate of reaction when the concentration of $X$ is $0.01 \, M$?

Similar Questions

$A$ first-order reaction takes $10 \ hours$ to complete $90\%$ of the reaction. How much time will it take to complete $99.9\%$ of the reaction (in $hours$)?

For the first-order gaseous reaction $A_{(g)} \to 2B_{(g)} + C_{(g)}$,the expression for the rate constant $K$ in terms of initial pressure $P_0$ and total pressure $P_t$ at time $t$ is:

If a $75\%$ first-order reaction is completed in $32 \text{ minutes}$,how many minutes will it take for the same reaction to be $50\%$ completed?

Half-life for a first order reaction is $6.93 \ hour$. What is the time required for $80 \%$ completion of the reaction (in $hours$)?

$A$ reaction has a rate constant $k = 2.4 \times 10^{-4} \ s^{-1}$. Find the ratio of $t_{99.9}$ to $t_{50}$.

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