An element has an atomic number of 17. The nu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electronic configuration of an element with atomic number $17$ $(Cl)$ is $1s^2 2s^2 2p^6 3s^2 3p^5$.The valence shell is the $n=3$ shell.The o

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) The electronic configuration of an element with atomic number $17$ $(Cl)$ is $1s^2 2s^2 2p^6 3s^2 3p^5$.The valence shell is the $n=3$ shell.The orbitals in the valence shell are $3s$ and $3p$.The $3s$ orbital contains $2$ electrons (one pair).The $3p$ subshell has $3$ orbitals $(3p_x, 3p_y, 3p_z)$.With $5$ electrons in the $3p$ subshell,the distribution is $(3p_x)^2 (3p_y)^2 (3p_z)^1$.Thus,there are two pairs in the $3p$ subshell and one pair in the $3s$ orbital.Total number of orbitals containing electron pairs = $1$ $(3s)$ + $2$ $(3p_x, 3p_y)$ = $3$.

An element has an atomic number of $17$. The number of orbitals containing electron pairs in the valence shell will be .......

Similar Questions

In any atom,which sub-shell will have the highest energy among the following?

The total spin of an iron $(Fe)$ atom is .......

For the given quantum numbers $n$ and $l$ of electrons:
$(i) n = 4, l = 1$
$(ii) n = 4, l = 0$
$(iii) n = 3, l = 2$
$(iv) n = 3, l = 1$
Arrange them in the increasing order of their energy.

Which of the following orbitals are possible: $1p, 2s, 2p, 3f$?

An ion with a charge of $-2$ has the electronic configuration $1s^2, 2s^2, 2p^6$. Identify the ion.

Vedclass Test Series

Exam Paper Generator

Online Exam Module