(C) The $e/m$ ratio (specific charge) is calculated as the ratio of charge $(e)$ to mass $(m)$.For $D^{+}$ $(_{1}H^{2})$: $e/m = 1/2 = 0.5$For $He^{+}

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(C) The $e/m$ ratio (specific charge) is calculated as the ratio of charge $(e)$ to mass $(m)$.For $D^{+}$ $(_{1}H^{2})$: $e/m = 1/2 = 0.5$For $He^{+}$ $(_{2}He^{4})$: $e/m = 1/4 = 0.25$For $H^{+}$ $(_{1}H^{1})$: $e/m = 1/1 = 1.0$For $He^{2+}$ $(_{2}He^{4})$: $e/m = 2/4 = 0.5$Comparing the values,$H^{+}$ has the maximum $e/m$ ratio.