In an orbital,the value of K.E. is equal to: | vedclass

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(A) According to the Bohr model for a hydrogen-like atom,the total energy $(E)$,kinetic energy $(K.E.)$,and potential energy $(P.E.)$ are related as f

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Half of the potential energy

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(A) According to the Bohr model for a hydrogen-like atom,the total energy $(E)$,kinetic energy $(K.E.)$,and potential energy $(P.E.)$ are related as follows:$E = -K.E.$$P.E. = 2 	imes E$Substituting $E = -K.E.$ into the potential energy equation,we get:$P.E. = 2 	imes (-K.E.)$$P.E. = -2 	imes K.E.$Therefore,$K.E. = -\frac{1}{2} P.E.$In terms of magnitude,the kinetic energy is half of the potential energy.

In an orbital,the value of $K.E.$ is equal to:

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