A neutral atom has 2, 8, and 7 electrons in i | vedclass

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(D) The electronic configuration of the atom based on the given shell distribution $(K=2, L=8, M=7)$ is as follows:$K$ shell $(n=1)$: $1s^2$ (contains

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$11$

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(D) The electronic configuration of the atom based on the given shell distribution $(K=2, L=8, M=7)$ is as follows:$K$ shell $(n=1)$: $1s^2$ (contains $2$ electrons)$L$ shell $(n=2)$: $2s^2 2p^6$ (contains $8$ electrons)$M$ shell $(n=3)$: $3s^2 3p^5$ (contains $7$ electrons)Total electrons in $p$-orbitals = (electrons in $2p$) + (electrons in $3p$)Total = $6 + 5 = 11$ electrons.Therefore,the correct option is $D$.

$A$ neutral atom has $2, 8,$ and $7$ electrons in its $K, L,$ and $M$ shells,respectively. What is the total number of electrons in the $p$-orbitals?

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