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(C) Given: Mass $m = 9.1 	imes 10^{-31} \, kg$,Velocity $v = \frac{1}{10} 	imes c = \frac{1}{10} 	imes 3 	imes 10^8 \, m/s = 3 	imes 10^7 \, m/s$

Vedclass · Accepted Answer

$2.426 	imes 10^{-11} \, m$

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(C) Given: Mass $m = 9.1 	imes 10^{-31} \, kg$,Velocity $v = \frac{1}{10} 	imes c = \frac{1}{10} 	imes 3 	imes 10^8 \, m/s = 3 	imes 10^7 \, m/s$,Planck's constant $h = 6.626 	imes 10^{-34} \, J \cdot s$.Using the de Broglie wavelength formula: $\lambda = \frac{h}{mv}$.$\lambda = \frac{6.626 	imes 10^{-34} \, J \cdot s}{(9.1 	imes 10^{-31} \, kg) 	imes (3 	imes 10^7 \, m/s)}$.$\lambda = \frac{6.626 	imes 10^{-34}}{27.3 	imes 10^{-24}} \, m$.$\lambda \approx 0.2427 	imes 10^{-10} \, m = 2.427 	imes 10^{-11} \, m$.

Calculate the wavelength of an electron if its mass is $9.1 \times 10^{-31} \, kg$,its velocity is $1/10$ of the speed of light,and the value of Planck's constant $h$ is $6.626 \times 10^{-34} \, J \cdot s$.

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