The electronic configuration of a nitrogen at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The atomic number of nitrogen $(N)$ is $7$. Its electronic configuration is $1s^2 2s^2 2p^3$.According to Hund's rule of maximum multiplicity,for

Vedclass · Accepted Answer

Vedclass · Answer

(A) The atomic number of nitrogen $(N)$ is $7$. Its electronic configuration is $1s^2 2s^2 2p^3$.According to Hund's rule of maximum multiplicity,for a given electron configuration,the term with the maximum multiplicity has the lowest energy. This means that electrons in the same subshell should occupy separate orbitals with parallel spins as far as possible.In the $2p$ subshell,there are $3$ electrons. Therefore,they should occupy the three $2p$ orbitals singly with parallel spins.Option $A$ (image $203-$a248) correctly shows $1s^2$ (paired),$2s^2$ (paired),and $2p^3$ (three unpaired electrons with parallel spins).

The electronic configuration of a nitrogen atom in its ground state is represented as follows:

Similar Questions

Give the symbol of the element with the lowest atomic number that has three $2p$ electrons.

How many orbitals are present in the $4^{th}$ shell with $\ell = 2$?

Which of the following rules states that an orbital can hold a maximum of two electrons?

Number of unpaired electrons in the ground state of beryllium atom is

Which of the following elements has the last electron in its outermost orbit with a magnetic quantum number $m = 0$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module