The energy of one mole of photons of radiatio | vedclass

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Question

(B) The energy of one photon is given by $E = h
u$. Given: $h = 6.626 	imes 10^{-34} \, J \cdot s$ and $
u = 5 	imes 10^{10} \, s^{-1}$. Energy of

Vedclass · Accepted Answer

$19.93$

Vedclass · Answer

(B) The energy of one photon is given by $E = h
u$. Given: $h = 6.626 	imes 10^{-34} \, J \cdot s$ and $
u = 5 	imes 10^{10} \, s^{-1}$. Energy of one photon = $(6.626 	imes 10^{-34} \, J \cdot s) 	imes (5 	imes 10^{10} \, s^{-1}) = 3.313 	imes 10^{-23} \, J$. Energy of one mole of photons = (Energy of one photon) $	imes$ (Avogadro constant $N_A$). Energy = $(3.313 	imes 10^{-23} \, J) 	imes (6.022 	imes 10^{23} \, mol^{-1}) \approx 19.95 \, J \, mol^{-1}$. Rounding to the nearest provided option,the answer is $19.93 \, J$.

Metal	$Li, Na, K, Mg, Cu, Ag, Fe, Pt, W$
$\phi \ (eV)$	$2.4, 2.3, 2.2, 3.7, 4.8, 4.3, 4.7, 6.3, 4.75$

The energy of one mole of photons of radiation whose frequency is $5 \times 10^{10} \, s^{-1}$ is .......... $J$.

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Photoelectric effect is the phenomenon in which

The work function $(\phi)$ of some metals is listed below. The number of metals which will show photoelectric effect when light of $300 \ nm$ wavelength falls on the metal is

Metal $Li, Na, K, Mg, Cu, Ag, Fe, Pt, W$

$\phi \ (eV)$ $2.4, 2.3, 2.2, 3.7, 4.8, 4.3, 4.7, 6.3, 4.75$

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