The mass of a particle is 1 , mg and its velo | vedclass

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(B) Given: Mass $m = 1 \, mg = 1 	imes 10^{-3} \, g$,Velocity $v = 4.5 	imes 10^5 \, cm/s$,Planck's constant $h = 6.652 	imes 10^{-27} \, erg \cdot

Vedclass · Accepted Answer

$1.4722 	imes 10^{-29} \, cm$

Vedclass · Answer

(B) Given: Mass $m = 1 \, mg = 1 	imes 10^{-3} \, g$,Velocity $v = 4.5 	imes 10^5 \, cm/s$,Planck's constant $h = 6.652 	imes 10^{-27} \, erg \cdot s$. According to the de Broglie equation: $\lambda = \frac{h}{mv}$. Substituting the values: $\lambda = \frac{6.652 	imes 10^{-27} \, erg \cdot s}{(1 	imes 10^{-3} \, g) 	imes (4.5 	imes 10^5 \, cm/s)}$. $\lambda = \frac{6.652 	imes 10^{-27}}{4.5 	imes 10^2} \, cm$. $\lambda = 1.4782 	imes 10^{-29} \, cm$ (approximately $1.4722 	imes 10^{-29} \, cm$ based on provided options).

The mass of a particle is $1 \, mg$ and its velocity is $4.5 \times 10^5 \, cm/s$. What will be the wavelength of this particle? $(h = 6.652 \times 10^{-27} \, erg \cdot s)$.

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