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(B) The de Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{mv}$.Given:Mass $m = 60 \ g = 60 	imes 10^{-3} \ kg = 0.06 \ kg$.

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$10^{-33} \ m$

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(B) The de Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{mv}$.Given:Mass $m = 60 \ g = 60 	imes 10^{-3} \ kg = 0.06 \ kg$.Velocity $v = 10 \ m/s$.Planck's constant $h = 6.626 	imes 10^{-34} \ J \cdot s$.Substituting the values:$\lambda = \frac{6.626 	imes 10^{-34}}{0.06 	imes 10} = \frac{6.626 	imes 10^{-34}}{0.6} \approx 1.1 	imes 10^{-33} \ m$.Thus,the value is approximately $10^{-33} \ m$.

The de Broglie wavelength of a tennis ball of mass $60 \ g$ moving with a velocity of $10 \ m/s$ is approximately ........

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