Identify the correct increasing order of e/m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The $e/m$ ratio (specific charge) for the given particles is calculated as follows:For neutron $(n)$: $\frac{e}{m} = \frac{0}{1} = 0$For alpha par

Vedclass · Accepted Answer

$n, \alpha, p, e$

Vedclass · Answer

(D) The $e/m$ ratio (specific charge) for the given particles is calculated as follows:For neutron $(n)$: $\frac{e}{m} = \frac{0}{1} = 0$For alpha particle $(\alpha)$: $\frac{e}{m} = \frac{2}{4} = 0.5$For proton $(p)$: $\frac{e}{m} = \frac{1}{1} = 1$For electron $(e)$: $\frac{e}{m} = \frac{1}{1/1837} = 1837$Comparing these values,the increasing order is $n < \alpha < p < e$. Therefore,the correct option is $D$.

Identify the correct increasing order of $e/m$ ratio for the following particles: $n, p, e, \alpha$.

Similar Questions

$A$ particle having the same charge and $200$ times greater mass than that of an electron is:

The number of electrons in the nucleus of $^{12}C$ is

The discovery of the neutron occurred very late because:

The mass of a neutron is nearly

Arrange the $\frac{e}{m}$ (charge-to-mass) ratio in increasing order for the following particles: $e, p, n, \alpha$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module