When an electron transitions from n = 4 to n | vedclass

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Question

(B) The Rydberg formula for the spectral lines of hydrogen is given by $\frac{1}{\lambda} = R_H 	imes Z^2 	imes (\frac{1}{n_1^2} - \frac{1}{n_2^2})$

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Second line of Balmer series

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(B) The Rydberg formula for the spectral lines of hydrogen is given by $\frac{1}{\lambda} = R_H 	imes Z^2 	imes (\frac{1}{n_1^2} - \frac{1}{n_2^2})$.For the Balmer series,the transition ends at $n_1 = 2$.The lines in the Balmer series are defined by transitions from $n_2 = 3, 4, 5, \dots$ to $n_1 = 2$.- The first line $(H_\alpha)$ corresponds to $n = 3 	o n = 2$.- The second line $(H_\beta)$ corresponds to $n = 4 	o n = 2$.Therefore,the transition from $n = 4$ to $n = 2$ represents the second line of the Balmer series.

When an electron transitions from $n = 4$ to $n = 2$,the emitted spectral line will be ........

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