For the H spectrum,the limiting line in the B | vedclass

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Question

(C) For the $Balmer$ series,$n_1 = 2$ and for the limiting line,$n_2 = \infty$. The Rydberg formula for frequency is $
u = R_\infty 	imes Z^2 	imes

Vedclass · Accepted Answer

$8.22 	imes 10^{14} 	ext{ s}^{-1}$

Vedclass · Answer

(C) For the $Balmer$ series,$n_1 = 2$ and for the limiting line,$n_2 = \infty$. The Rydberg formula for frequency is $
u = R_\infty 	imes Z^2 	imes (\frac{1}{n_1^2} - \frac{1}{n_2^2})$. Substituting $Z = 1$,$n_1 = 2$,and $n_2 = \infty$: $
u = 3.29 	imes 10^{15} 	imes (\frac{1}{2^2} - \frac{1}{\infty^2}) 	ext{ s}^{-1}$. $
u = 3.29 	imes 10^{15} 	imes \frac{1}{4} 	ext{ s}^{-1} = 8.225 	imes 10^{14} 	ext{ s}^{-1}$.

For the $H$ spectrum,the limiting line in the $Balmer$ series has a frequency of ...... $(R_\infty = 3.29 \times 10^{15} \text{ cycles/s})$

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