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(B) The $e/m$ ratio (specific charge) for the given particles is as follows:$1$. For neutron $(n)$: Charge is $0$,so $e/m = 0$.$2$. For $\alpha$-parti

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$n, \alpha, p, e$

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(B) The $e/m$ ratio (specific charge) for the given particles is as follows:$1$. For neutron $(n)$: Charge is $0$,so $e/m = 0$.$2$. For $\alpha$-particle $(\alpha)$: Charge is $+2e$ and mass is $4u$,so $e/m \approx 0.5 	imes (e/m 	ext{ of proton})$.$3$. For proton $(p)$: Charge is $+e$ and mass is $1u$,so $e/m = 9.58 	imes 10^4 \, C/g$.$4$. For electron $(e)$: Charge is $-e$ and mass is $1/1837 \, u$,so $e/m = 1.76 	imes 10^8 \, C/g$.Comparing these values: $0 Thus,the increasing order is $n < \alpha < p < e$.

Arrange the following particles in the increasing order of their $e/m$ ratio: electron $(e)$,proton $(p)$,neutron $(n)$,and $\alpha$-particle $(\alpha)$.

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