The coordination number of $Cs^+$ in the crystal of $CsCl$ is ......

Predict the close-packed structure of an ionic compound $A^{+} B^{-}$ in which the radius of cation and anion are $148 \ pm$ and $195 \ pm$ respectively.

The crystal $AB$ has a structure similar to $NaCl$. Atoms of $A$ are present at each corner of the cubic unit cell. If all atoms along one of the axes passing through the face centers are removed,what will be the resulting stoichiometry?

In an ${A^{+}}{B^{-}}$ ionic compound, the radii of ${A^{+}}$ and ${B^{-}}$ ions are $180 \ pm$ and $187 \ pm$ respectively. The crystal structure of this compound will be:

In the calcium fluoride structure,the coordination number of the cation and anion are respectively:

In an end-centered unit cell,the body diagonal contains two additional atoms. What is the total number of atoms present in the unit cell?