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(B) The reaction of sodium thiosulphate $[Na_2S_2O_3]$ with dilute $HCl$ produces sulphur dioxide gas $[SO_2]$ and a yellow precipitate of sulphur $[S

Vedclass · Accepted Answer

$Na_2S_2O_3, SO_2, Cr_2(SO_4)_3$

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(B) The reaction of sodium thiosulphate $[Na_2S_2O_3]$ with dilute $HCl$ produces sulphur dioxide gas $[SO_2]$ and a yellow precipitate of sulphur $[S]$.$Na_2S_2O_3 + 2HCl \rightarrow 2NaCl + SO_2 \uparrow + S \downarrow + H_2O$$(A) = Na_2S_2O_3, (B) = SO_2$When $SO_2$ gas is passed through acidified potassium dichromate $(K_2Cr_2O_7 + H_2SO_4)$,it reduces $Cr^{6+}$ to $Cr^{3+}$,resulting in a green solution of chromium$(III)$ sulphate $[Cr_2(SO_4)_3]$.$K_2Cr_2O_7 + H_2SO_4 + 3SO_2 \rightarrow K_2SO_4 + Cr_2(SO_4)_3 + H_2O$$(C) = Cr_2(SO_4)_3$Therefore,the correct sequence is $Na_2S_2O_3, SO_2, Cr_2(SO_4)_3$.

$A$ white crystalline salt $[A]$ reacts with dilute $HCl$ to produce a suffocating gas $[B]$ and also forms a yellow precipitate. When gas $[B]$ is passed through acidified potassium dichromate,it turns the solution green,forming $[C]$. Identify $A, B$,and $C$ respectively.

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