Which of the following compounds will give a | vedclass

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(A) $1$. $Pb(NO_3)_2$ reacts with $NaCl$ to form $PbCl_2$ (white precipitate),while $Ba(NO_3)_2$ reacts with $NaCl$ to form $BaCl_2$ (soluble in water

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$NaCl$

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(A) $1$. $Pb(NO_3)_2$ reacts with $NaCl$ to form $PbCl_2$ (white precipitate),while $Ba(NO_3)_2$ reacts with $NaCl$ to form $BaCl_2$ (soluble in water).$2$. $Pb(NO_3)_2$ reacts with sodium acetate to form lead acetate (soluble),while $Ba(NO_3)_2$ also forms soluble barium acetate.$3$. Sodium nitrate does not form a precipitate with either.$4$. Sodium hydrogen phosphate $(Na_2HPO_4)$ forms precipitates with both $Pb^{2+}$ and $Ba^{2+}$ ions.$5$. Therefore,$NaCl$ is the correct answer as it selectively precipitates $Pb^{2+}$ as $PbCl_2$.

Column-$I$	Column-$II$
$(P) NaBr + \text{conc. } H_2SO_4 \rightarrow$	$(A) \text{Colourless gas}$
$(Q) Na_2S + \text{dil. } HCl \rightarrow$	$(B) \text{Brown colour}$
$(R) NaNO_2 + \text{dil. } HCl \rightarrow$	$(C) \text{Rotten smell}$
$(S) NaNO_3 + \text{conc. } H_2SO_4 \rightarrow$	$(D) \text{Paramagnetic}$

Which of the following compounds will give a precipitate with $Pb(NO_3)_2$ but will not give a precipitate with $Ba(NO_3)_2$?

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