Concentrated $HCl$ is $10 \,N$. How can $1000 \,cc$ of $1 \,N \,HCl$ be prepared by dilution?
- A$1 \,cc$ of concentrated $HCl$ diluted to $1000 \,cc$
- B$10 \,cc$ of concentrated $HCl$ diluted to $1000 \,cc$
- C$20 \,cc$ of concentrated $HCl$ diluted to $1000 \,cc$
- D$100 \,cc$ of concentrated $HCl$ diluted to $1000 \,cc$
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